Hey guys,
I really appreciate all of you who have been sub..
🕑 Added 2023-07-25 13:00:29 +0000 UTC
Hey guys,
I really appreciate all of you who have been subscribers up to this point. As you probably know, I take pride in being able to say that I personally respond to my messages. You always get the real me. No management company. No paid chatters. No bots. Just ME! ππ»ββοΈ
As my page grows it becomes harder to do this especially with a lot of scammers and spammers jumping in on a free page and flooding my messages. π‘
For this reason, Iβve decided to change my page to a subscription only model. I will be making this change sometime in the next week or so and wanted to give everyone advance notice. π
This change allows me to weed out people who arenβt contributing and focus my energy on my loyal, paying fans, and continue to make the best high quality content. π€©
What can you expect from my new page? π§
No PPV (Pay Per View) for my content. You will no longer have to pay for individual photo sets and videos. Once you pay the monthly subscription price, all of my content will be unlocked for no additional fees! π
For those of you who actually purchase my content, this means you can get all that would normally have cost you $30, $40, $50+ per month in PPVs in one much lower monthly fee! I am leaning towards a price point of $15/month. β
I also have recently obtained new and better lighting and the quality of my new content is improving all the time. You can expect regular high quality photos and videos posted to my page each week. πΈ
You will be still able to make requests for custom videos and photos for your special desires as per the prices on my tip menu. π
Be patient with me as I make the transition but in the end I think you will be very pleased with the final outcome! π―
For those of you who choose not to pay the subscription, I hate to lose you, but I understand. Iβd encourage you to follow me on Instagram and Twitter to stay in touch, but unfortunately the GOOD stuff will be right HERE. π
Thanks,
Indiyah π
